# NumPy Any: Understanding np.any()

Ben Cook • Posted 2021-10-21

The `np.any()` function tests whether any element in a NumPy array evaluates to true:

``````np.any(np.array([[1, 0], [0, 0]]))

# Expected result
# True``````

The input can have any shape and the data type does not have to be boolean (as long as it’s truthy). If none of the elements evaluate to true, the function returns false:

``````np.any(np.array([[0, 0], [0, 0]]))

# Expected result
# False``````

Passing in a value for the `axis` argument makes `np.any()` a reducing operation. Say we want to know which rows in a matrix have any truthy elements. We can do that by passing in `axis=-1`:

``````np.any(np.zeros((2, 3)), axis=-1)

# Expected result
# array([False, False])``````

There are two rows and for each of them, none of the elements evaluate to true. The `-1` value here is shorthand for “the last axis”.

Easy enough! NumPy also has a function called `np.all()` which has the same API as `np.any()` but returns true when all of the elements evaluate to true.